CH3 CH2 CHCH 3 CH3=CHCH3 CH3CH2CH=CH 150°C 2 +N(CH3)3 5% 95% OH +( cH3)3N+ H2O HO--H HO--H N(CH3)3 E2消除,过渡态类似于烯 “准”负碳离子过渡态 CH 3 PhCH2 CH2NCH2CH 3 PhCH=CH2 +(CH3)2NCH2CH3 CH3 OH 生成苯乙烯而不是乙烯CH3CH2CHCH3 N(CH3)3 OH 150 o C CH3CH=CHCH3 + CH3CH2CH=CH2 5% 95% + (CH3)3N + H2O H C X C HO E2消除，过渡态类似于烯 H C N(CH3)3 C HO  -  - “ 准” 负碳离子过渡态 PhCH2CH2NCH2CH3 PhCH=CH2 + (CH3)2NCH2CH3 CH3 CH3 OH  生成苯乙烯而不是乙烯