圈上泽充大峰 Load Raising-Loosening Screw Eliminating the normal force gives: 月=Pfcos-sinA到 (cos f sin tan=I1(πdm). Dividing both numerator and denominator by cosλgies: P= F[f-(lπd,)】 1+(fl/πdn） 圆上清支大华 Load Raising-Loosening Screw The torque for lowering the load is a product of the force P and the mean radius or dm/2. Fdn fd 2 ndmf This torque is responsible for overcoming thread friction and to lower the load. 2323  Eliminating the normal force gives: tan  = l / ( dm).  Dividing both numerator and denominator by cos  gives:     cos sin cos sin L f P F f          1  m L m Ff l d P fl d          Load Raising- Loosening Screw  The torque for lowering the load is a product of the force P and the mean radius or dm / 2.  This torque is responsible for overcoming thread friction and to lower the load.           d fl Fd fd l T m m m   － 2 Load Raising- Loosening Screw