B:等压过程QB=Cp△T (2) 解(1)(2)联立得 △T C +.ii+2 r+ R 335 =6.72K i+1)R(5+1)8.31 i+2 QB=C,△T R△T 5+2 8.31×6.72=196J 5 Q4=CAT=R△T=×8.31×672=139J (或Q4=Q-Qn=335-196=139J3 B :等压过程 Q C T(2) B = P  解(1)(2)联立,得 ( ) ( ) K i R Q R i R i Q C C Q T V P 6.7 2 5 1 8.3 1 335 1 2 2 2 = + = + = + + = +  = J R T i QB CP T 8.31 6.72 196 2 5 2 2 2  = + =  + =  = ( 335 196 139 ) 8.3 1 6.7 2 139 2 5 2 Q Q Q J R T J i Q C T A B A V = − = − = =  =  =   = 或