ar1 aY sin0-)+ sn606 a0 sm 8002+1(1+1)Y=0 b.球方程再令 Y(6,q)=(6d(q) d 0 sin b3+l(1+1)=0 sine d 1a2Φ (Sn6,-)+l(+1)sn2b= 0 o de +A=0 d sin 0(sin 0)+[(+Isn 8-nJ0=0 deb. 球方程 再令 Y(,) = ( )() ( 1) 0 sin (sin ) sin 2 2 2 + +  =   +   l l d d d d d d       0 1 (sin ) ( 1)sin sin 2 2 2 =   + + = −         d d l l d d d d 0 2 2 +  =   d d sin (sin ) [ ( 1)sin ] 0 2 + + −  =        l l d d d d ( 1) 0 sin 1 (sin ) sin 1 2 2 2 + + =   +     l l Y Y Y      