解： J=2MR2-5x1g15-5.2x102k3m2 2 (1)w=2Tn=t ω2n2×3.14×10 a=t= t 0.5 =1.26×1021/s2 0= 1ut2-号×1.26×102×0.52=5m N=2=2.5rev 结束目录 5.2×10-2 kg.m2 = =1.26×102 1/s2 = = = ω a t 2πn t 2×3.14×10 0.5 1.26×102×(0.5)2 = 5π 2 1a t 2 q = = 2 1× N= q 2π = 2.5rev (1) ω= 2πn=a t 2 5 0.15 J MR 2 2 1 × = = ( ) 解： 2 结束 目录