Continue Example 37.1 D.ir=mr(u-)+P.(Vi-V)-mT.(S-S) Continue Solution: Volume of air dead state: V。=Var(To,Po)≠V V= 3484kg287KgK3 300K 1Nm Po 1-10mw V。=3.0m3 →Φ，1=3.484kg(286.16-214.07) +100kPa(0.4-3.0)m kN/mIk] k k 1kPa 1kNm -3484kg30K(-0.37)）kKK Φ，=369kJ air. 上降道学 May2,2018 13 SHANGHAI JIAO TONG UNIVERSITYMay 2, 2018 13 Continue Example 37.1   2 o air o o 1 air o o 5 o 3 o J kg K N m V V T ,p V 3.484kg 287 300K 1Nm m RT V p 1 10 1J V 3.0m             2 3 air,1 air,1 kJ kN m 1kJ 3.484kg 286.16 214.07 100kPa 0.4 3.0 m kg 1kPa 1kNm kJ 3.484kg 300K 0.371 kg K 369kJ  F       F   Continue Solution: » Volume of air @ dead state: F    air,1 o   m u u air 1 o   po V T 1 o V  mair s1 o s  ??