三、积分性质 设￡If(=F(S) ￡d=专S) ve=fiad :设[ic]=I(s) u.1=id-0)+61因 四、延迟性质 若￡[f()=F(S) 则￡[f(t-t)】=estF(S) u(t)=(t)-(t-to) u(坊 E[u(t)] =￡[&(t)]-￡[e(t-t)] 11 e-sto to SS ഋǃᔦ䘏ᙗ䍘 㤕 £ [f (t)]=F (S) ࡉ] £ f (t-t0 )]=e-st0F (S) u(t) = 0 İ(t) - İ(t - t ) 0 u(t) t0 t 1 0 - £[ ( )] £[ ( )] 1 1 st u t t e s s H  0   £[ ( )] H t t £ [³ f(x)dx]= F(S) 0- t 1 S йǃ〟࠶ᙗ䍘 䇮 £ [f (t)]=F (S) C C ³ 1 u = i dt C 䇮 (0 )   u ³ £ £ £ C C C CC C [i ]= I (s) 1 1 11 [u ]= [ i dt]= u I (s) C s Cs