正在加载图片...
△相S1=nAyap Hm/T A,-C-H0副r=Kom,0gn2 T dS,=nC,H0h2+△≥-+nC,(H,0g T 373.15.x4059×10+1×33.6xn 323.15 =(1×73.5ln )J.K- 323.15 373.15 373.15 =114.52JK-1 1 2 , 2 , 2 3 (H O, )ln (H O, ) 2 1 T T dT nC g T nC g S p m TT p m ∆ = = ∫ 1 1 ∆相S = n∆vapHm /T 1 2 , 2 2 1 1 2 , 2 (H O,1)ln (H O, )ln TT nC g TH TT S nC p m vap m p m + ∆ ∆相 = + 1 3 )J K 373.15 323.15 1 33.6 ln 373.15 1 40.59 10 323.15 373.15 (1 73.5ln − + × × ⋅ × × = × + =114.52 J·K-1
<<向上翻页向下翻页>>
©2008-现在 cucdc.com 高等教育资讯网 版权所有