π 11 =1- 一一一十 程序解析一求π的近似值 4 357 #include<stdio.h> #include <stdio.h> #include <math.h> #include <math.h> void main() void main() int denominator,flag; int s; double item,pi; float n,t,pi; flag =1;denominator=1 item =1 t=1;s=0;n=1.0;m=1 while(fabs (item)>=0.0001) while((fabs(t))>=1e-6) item flag 1.0/denominator; {S=S+t街 pi=pi item; n=n+2; flag -flag; m=-m; denominator denominator +2; } t=m/n; pi=pi 4; printf(“pi=%fn”,pi); pi=s*4; printf("pi=%fn",pi);1 1 1 1 4 3 5 7  = − + − + 程序解析－求π的近似值 #include<stdio.h> #include <math.h> void main( ) { int denominator, flag; double item, pi; flag = 1; denominator = 1 ; item = 1.0; pi = 0; while(fabs (item) >= 0.0001) { item = flag * 1.0 / denominator; pi = pi + item; flag = -flag; denominator = denominator +2; } pi = pi * 4; printf ( “pi = %f\n”, pi); } item=0.0 ? #include <stdio.h> #include <math.h> void main() { int s; float n,t,pi; t=1; s=0; n=1.0; m=1; while((fabs(t))>=1e-6) { s=s+t; n=n+2; m=-m; t=m/n; } pi=s*4; printf("pi=%f\n",pi); }