例:若:p 100=100kPa 101 101325kPa 求证:Km/K1=(101325/100 ⊙ ⊙ Go-△G 100 101S ∑ VeRTI(101.325/100) 解z0=Kn(p9)2=kn×(100Pa)2N K01=Kn(p3)2=Kn×(101325Pa)2 所以:A 100 100 ∑V 101325 ∑V 101325 100 101例： 若： p100 = 100kPa  p 101.325kPa Θ 101 = 求证：  = K Θ K Θ ν B / (101.325 / 100) 100 101 Δ Δ ν ln(101.325 / 100) Θ 101 Θ G100 − G = − B RT 解： − − = =  B B K K p K kPa p p Θ ν 100 ( ) (100 ) Θ ν − − = =  B B K K p K kPa p p Θ Θ ν ν ( ) (101.325 ) 101 所以：   = = − B B K K ν ν Θ 101 Θ 100 ) 100 101.325 ) ( 101.325 100 (