EXAMPLE 1.2 THE LIVING PERSON A human being (75 kg)consumes about 6000 kJ of food per day.Assume that the food is all glucose and that the overall reaction is C6H1206+602→6C02+6H20,-4H,=2816kJ from air breathed out Find man's metabolic rate (the rate of living,loving,and laughing)in terms of moles of oxygen used per m3 of person per second. SOLUTION We want to find 1 dNo: mol O2 used () (m3 of person)s Let us evaluate the two terms in this equation.First of all,from our life experience we estimate the density of man to be P=1000kg n 1717