④热力学处理 1)求Kc≠ A+BC学IA.B.CY 标态：△G4m0,AHm,△rS4m0 △Gm°=-RTInKc- 0 △Gm0=A,Hm0-TArS4m0 △，Gm △，S9m_A,H9m =e RT =e R e RT 19 19 ④热力学处理 标态：rGm 0 ，rHm 0 ，rSm 0 rGm 0 = -RT ln KC 0 rGm 0 = rHm 0 - TrSm 0 RT H R S RT G c r m r m r m K e e e 0 0 0     −   −  = = 1）求 KC