K (2)图中直线斜率为 -△,H/R}=200×103 △H=200×103×8.314×103kJmr -166kI-morI A, Gm (298K)=-RTInK(298K) 8314×10-3×298 K]. mot In689 16.2 KJ mol3.0 3.2 3.4 3.6 6.0 6.2 6.4 6.6 6.8 7.0 7.2 B lnK 1 3 10 T ¥ K 1 (2)图中直线斜率为 3 {-DrHm / R} = 2.00¥ 10 则 DrH =2.00×10 3×8.314×10 3 kJ∙mol1 = -16.6 kJ∙mol1 (3) (298 ) ln (298 ) DrGm K = -RT K K = 8.314×10 3×298 KJ∙ mol1 ln689 = 16.2 KJ ∙mol1