习题5(5.(2) -ab ac ae 计算 bd -ed de =4abcdef. bf cf-ef 解 所有字母都可以作为公因子提出来，剩下一个常数行列式 习题6(5.(4) 计算 =-10- 0 合、 张莉(Tongji University) 线性代数 5/60SK5 (5.(2)) Oé         −ab ac ae bd −cd de bf cf −ef         = 4abcdef. ) §ki1—å±äè˙œfJ—5ßêeòá~Í1™. SK6 (5.(4)) Oé               0 1 2 . . . n − 1 n 0               = (−1)n−1n!. ) U1ò–m. ½r1òÅ￾òßzèÈ . ‹s (Tongji University) Ç 5 ì Í 5 / 60