Another Example of First-Order System Cde(t)=q(t)dt 900=-6 R Θ+θ(t) de(t) =q0）= e。-(t) ⊙+0n dt R ⊙+0。 Rcd90+80）=9, C(kcal/C):thermal capacitance dt R(C/kcal/s):thermal resistance q (kcal/s):heat input 1 1 ⊙，(s) RCs+1 Ts+1Another Example of First-Order System    b    ( )t Cd t q t dt  () ()  • C (kcal/ oC): thermal capacitance • R ( oC/kcal/s): thermal resistance • q (kcal/s): heat input ( ) ( ) b t q t R     () () ( ) b dt t C qt dt R      ( ) ( ) b d t RC t dt        b () 1 1 () 1 1 b s s RCs Ts      