Lab=300sm(2000+)mV,tia()=5sm(200)my (1)=100ms时,uab、iat分别为 L24(0.)=3005m(2000×0.1+)=300sm /=-150mk Zlb(0.1)=5sm(2000x×01-2 )=sin 4.33mA 3 (2)Lin(1)=-iab=5sm(2000n +x)=5sm(2000m+ 2兀)mA 0(0.)=5sm 2兀)=4.3m4 412相位差 1.相位差 两个同频率的正弦量 l1(=U/1mSin(O计+g1) u2 (t=U2m sin(at+o 2)4.1.2 1. 相位差 两个同频率的正弦量 u 1 (t)=U 1m sin(ωt+φ1 ) u 2 (t)=U 2m sin(ωt+φ 2 ) t mV t t mV ua b ia b 300sin( 2000 ) , ( ) 5sin( 2000 ) 6 3   =  + =  (1) t=100 ms时， u ab 、 i ab分别为 =  − = = −  =  + = = m m V u u a b a b (0.1) 5sin( 2000 0.1 ) 5sin 4.33 (0.1) 300sin( 2000 0.1 ) 300sin 150 3 3 6 6       t t t mA ib a ia b ( ) sin( 2000 ) sin( 2000 ) 3 2 5 3 5   （ = − =  − + =  + 2） mA ib a 4.33 3 2 (0.1) = 5 sin( ) = 