1.输入相位阶跃:(1)一阶PLL F (s)= 1(t) 5+kG1(S)=-40 stK P △O 02(t)=△Oe △6 (∞)= lim S 62(s) s→>0 △O lim 0 △6 s→>0 K 1+2P 01 . 输入相位阶跃：（1）一阶PLL HF (s) =1 K t e p t e −  ( ) =   t t t 0 0 0 (t)  e ( ) 1  t ( ) 2  t  0 1 lim ( ) lim ( ) 0 0 = +  =  =  → → s K s s P s e s e    p p e s K s s K s s +  = + =   ( )  ( ) 1  