CH+C2H2=CE+C2ES2 (5) CH21+C2H22=CES2+C2E 其中 H=∫AH4drdr2=2E。+元+K H2=2E++K Hi2 =Hdudr2 =(2E+)S2+A H21=(2E+发)S2+A K=∫iAi2[层-后-云]Mu42dr,dr2 A=∫p42[后-后-乐]p24dr,dr, S2=∫piup2p24udr,dr2 C[E-(2E。+装+K]+C,{[E-(2E。+JS2-A=0 CE-SCE-+0......( 5 ) 2 2 1 2 1 2 2 2 1 2 1 1 1 2 1 2 1 2        C H C H C ES C E C H C H C E C ES 其中 ......(6) {[ (2 )] } [ (2 )] 0 [ (2 )] {[ (2 )] } 0 2 2 2 2 2 0 2 1 0 2 1 0 2 0                  C E E S A C E E K C E E K C E E S A Re Re Re Re ∴ 2 * 11 1 1 1 2 0 2 e H H d d E K R           2 22 0 2 e H E K R    2 * 2 12 1 2 1 2 0 (2 ) e H H d d E S A R           2 2 21 0 (2 ) e H E S A R    2 2 2 12 2 1 * * (1) (2) (1) (2) 1 2 [ ] a b e e e K d d a b a b r r r           2 2 2 12 2 1 * * (1) (2) (2) (1) 1 2 [ ] a b e e e A d d a b a b r r r           2 * * a b a b (1) (2) (2) (1) 1 2 S d d        