dx 反应净速率y= =r+-r dt =k+(a-x)2-kx2 dx ba-对P-kx=. (c)平衡条件：r+=r. kr (a-xc)2=kx2 k K- (a-x)2 k 22 22 反应净速率 dt dx  = =r+-r- =k+（a-x）2 -k￾x 2   = + − − − x t dt k a x k x dx 0 0 2 2 ( ) （c）平衡条件：r+=r￾k+（a-xe）2 = k￾xe 2 − + = − = k k a x x K e e 2 2 ( )