(5) 2-2级可逆反应 ki A+B C+D k t=0 0 CA= CA0一X t=t CA XX CB-CBO-X r=k:CACB=k (CAo-x)(CBo-x) r-=kCcCp=kx 若Ca0Co=ar+=k(a-x)2 r-=kCcCp=kx 2121 (5) 2-2 级可逆反应 t=0 CA0 CB0 0 0 t=t CA CB x x CA= CA 0-x CB= CB 0-x r+=k+CACB=k+(CA0-x)(CB0-x) r-=k-CCCD=k-x 2 若 CA0=CB0=a r+=k+(a-x) 2 r-=k-CCCD=k-x 2