第五章导数和微分 sinclar (cos xInx +91) (20)Iny x lnx (xt)lnx y 又(xx)=x(lnx+1)故y=x2[x2lnx(nx+1)+x2-1 (21)y=ex·(-1)sin2x+e-2o2x:2=e-2(2o2x-in2x) [1+ 2 4 (23)y= cos[ sin(sinx)oos(sinr )cosc snT- aoT n sir ar (24)y SInT (25)y=>al(x-a) ) a t bsin.x acsr(a+bsinz)-boos.(asin+ b) (a +binz) cos. a+ binz I√a2-b2 6-1 cosx i a+ bint II cosr 4.对下列各函数计算∫(x),f(x+1),f(x-1) (1)f(x)=x3;(2)f(x+1)=x3;(3)f(x-1)=x 解(1)f(x)=3x2,f(x+1)=3(x+1)2,f(x-1)=3(x-12 112