(2)F(A,B,C)=(A+B)(AC)=ⅠM?) AF:F(A, B, C)=(A+B+CC)(A+C+BB) (A+B+CA+B+C(A+B+C) (A+B+C) =∏(0,1,3) βC00011110 A 00 00=∏M(?) 解: F( A , B , C ) = ( A+B+ C·C )(A+C+ B·B ) =(A+B+C)(A+B+C)(A+B+C) (A+B+C) = M0·M1·M3 = ∏ ( 0 , 1 , 3 )