Solution:Ideal gas model,Closed system 02: 20.15m2 138C R=260J/kg·K) 285℃ 月055M明 名0.7NMP CV 50.P 1 3 Cv=657J/(kg·K) cp=917J/(kg·K) 0.55×106Pa×0.15m3 =1.020kg RT 260J/(kg·K)×(273+38)K 0.7×106Pa×0.15m3 =0.274kg RT 260J/(kg·K)×(273+285)K 上游通大学 Mar/20,Mon,2017 6 SHANGHAI JLAO TONG UNIVERSITYMar/20, Mon, 2017 6 R   260 J/(kg K)   6 3 1 1 1 0.55 10 Pa 0.15 m 1.020 kg 260 J/(kg K) 273 38 K p V m RT           6 3 3 3 3 0.7 10 Pa 0.15 m 0.274 kg 260 J/(kg K) 273 285 K p V m RT         O2 : 657 J/(kg K) V c   917 J/(kg K) p c   Solution：Ideal gas model, Closed system