Solution System HO mr=1 kg V=6L How to determine U and U2? P=75 kPa (gage Vapor Liquid V0.006m3 0.006m3/kg 0.=500w = = m 1kg 1 - 0.006-0.001 0.00499 1.004-0.001 xu=uf+xiufs P =175 kPa = 486.82+(0.00499)(2037.7)kJ/kg=497kJ/kg T=TOp=116C 0 U1=m1w1=(1kg)(497kJ/kg)=497kJ ② m2 2=y+x2%=0.001+x2(1.004-0.001)m3/kg 3 42=4+24g=486.82+x2(2037.7)kJ/kg 0 U2=m2 上游充通大 Mar/29,Wed,2017 9 SHANGHAI JIAO TONG UNIVERSITYMar/29, Wed, 2017 9 Solution How to determine U1 and U2 ? U m u 2 2 2  2 3 4