4.解:J从0→1跃迁时 由:△=2B→B=2=10.30cm1=10.30×102m1 h B →I =2718×10kgm 87C 8丌2Bc H 1×35 23=1.63×10Kg n+mn(1+35)×6.02×10 2.718×10-47 =m2→r= 129.3Dm V-V1.53×10 271 2 1 10.30 10.30 10 2 ~ 2 ~ − − = =    = B  B = cm m   4 7 2 2 2 2.718 10 . 8 8 kg m Bc h I Ic h B − =  = =    4. 解：J从0→1跃迁时 由： K g N m N m N m N m H Cl H Cl 2 7 2 3 0 0 0 0 1.63 10 (1 35) 6.02 10 1 35 − =  +    = +   = pm I I r r 129.3 1.63 10 2.718 10 2 7 4 7 2 =   =  = = − −  