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5.(30 points)Figure below shows a pin-jointed plane truss discretized with 2 elements and 3 nodes.node 3 is fixed whereas 1 and 2 move over rollers as shown.Thec ero applied load acts upward on node 1.Solve this problem by the Start from the element stiffness equations given below.These are listed and already incorporate the E AL factor(stiffness factor for bar element)in the stiffness matrices. P=51 10,0 月302,0 →x (r v)node coordinate written in parenthesis E-200N2,.=3m 62 for both (1)and (2) after node numbers 26.-0 The element stiffness equations in global coordinates are as follows: 50-50-50 507 5050-50-507 -505050-50 5050-50-50 -50-505050 L-50-505050J (1)Assemble the master stiffness equations (2)Apply the given force and displacement BCs to get a reduced system of 2 equations and show it. (3)Solve the reduced stiffness system for the unknown displacements and show the complete node displacen nent vector. (4)Recover the axial force F(2)in element(2)using the displacements you got in (3),noting sign. Note:The displacement transformation is 0 0 -5c00 0 0 0 0 5. (30 points) Figure below shows a pin-jointed plane truss discretized with 2 elements and 3 nodes. Node 3 is fixed whereas 1 and 2 move over rollers as shown. The only nonzero applied load acts upward on node 1. Solve this problem by the Direct Stiffness Method. Start from the element stiffness equations given below. These are listed and already incorporate the E e A e /L e factor (stiffness factor for bar element) in the stiffness matrices. The element stiffness equations in global coordinates are as follows: (1) Assemble the master stiffness equations. (2) Apply the given force and displacement BCs to get a reduced system of 2 equations and show it. (3) Solve the reduced stiffness system for the unknown displacements and show the complete node displacement vector. (4) Recover the axial force F(2) in element (2) using the displacements you got in (3), noting sign. Note: The displacement transformation is
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