VHASCA ×0.1000×4545×10-3×74922 100%=22.7% 0.5000 6.解: 0580514236 M+35453107868+35453 故Ma=22989 7.解:设该铁的氧化物的分子式为FeOy,则 x55.85+y16=0.5434 x55.85=0.3801 解方程组,得x=0006806,y=001020 0.01020 0.006806 故为Fe2O34 1 1 3 0.1000 45.45 10 74.922 3 3 100% 100% 22.7% 0.5000 NH SCN As As s n M m ω − ⋅ × × × × = × = × = 6. 解： 0.5805 1.4236 35.453 107.868 35.453 M Na = + + 故 MNa = 22.989 7. 解：设该铁的氧化物的分子式为 FexOy ，则 55.85 16 0.5434 55.85 0.3801 x y x ⋅ + ⋅ = ⋅ = 解方程组，得 x=0.006806 , y=0.01020 0.01020 : 3: 2 0.006806 y x = = 故为 Fe2O3