C-3 8 16.61 -Numerical example for \ddot x 4 \dot x +3x=0 clear all T=0.05 号 actua1工C 号 start numerl.cs xml=x0-xOdot*T; NN=100; X=[xm1 x0] for li=3+[0: NN X(ii)=((4*+2)*X(ii-1)X(i-2))/(1+4*T+3*T~2) end 4 f );c1f sys=ss([01;-3-4],[01],[10],0 Y=initial(sys, [xo xOdot]',T*[0: NN]') 2.5 120