例1.解答(续) =122908V lZ3zn zi 1=4∠03A du Icet Z=RIXC=10-j2Q2 B Z,=R,=29 2 3=A=/2a22=22sm(100909A V U+z Z,Z,+ 12290°+4∠0°×2290° (10一j2)+j2 2290°A例1. 解答（续） 4 0 A 12 90 V =   =   I U   = =  = = −  Z 2 10 2 2 2 1 1 R Z R -jX j C Z3 = jXL = j2 + - C I  Z1 Z2 I U   A B Z3 1 3 3 1 1 Z Z I Z U VA + + =    2 90 A (10 2) 2 12 90 4 0 2 90 1 3 3 1 =   − +   +     = + + = = j j Z Z U IZ Z V I A C     i C = 2 2 sin(1000t +90)A