F=Pna sin eded 4Ta'e= 6tHUc 00 2a y 又解 F=e J(ORR COSB-O re sin )2ra sing a de e,2Ta [(Po BuU cos B coSH 2a sin O)]sin e de e 2Ta(Po cos 8 )sin e de e 2a Po sin 6 3uU 0cos‖=6 Tula e 2 2 02 2 2 0 0 3 sin 4 6 2 n z z U F p a d d a e Uae a    = = =        又解 : ( cos sin ) 2 sin z RR R A F e a a d = −          2 2 0 0 2 0 0 2 2 0 3 cos 3 2 [( )cos ( sin )]sin 2 2 3 2 ( cos )sin 2 sin 3 2 cos 6 2 2 0 z z z z U U e a p d a a U e a p d a p U e a Ua e a                      − = − + − = − +   − = − =        RR  R  R   P x y z a