Region of convergence(Roc) SIn w n n= coS( w on),hp[n 0o<n< oo Neither of them is absolutely summable neither of them multiplied byr-n(oo<n<oo) would be absolutely summable for any value of r Thus, neither them has a z-transform that converges absolutely 2021/1/31 Zhongguo Liu_ Biomedical Engineering_shandong Univ10 2021/1/31 Zhongguo Liu_Biomedical Engineering_Shandong Univ. Region of convergence (ROC)   sin , lp w nc h n  n x n w n [ ] cos , = ( 0 ) = ➢Neither of them is absolutely summable, neither of them multiplied by r-n (-∞<n<∞) would be absolutely summable for any value of r. Thus, neither them has a z-transform that converges absolutely. -∞<n<∞