Region of convergence(Roc) cos(wn)→∑[6(m-1+27)+6(m++27) k=-0 sin w n W<w H 0,w<w≤x >The fourier transforms are not continuous infinitely differentiable functions so they cannot result from evaluating a z-transform on the unit circle. it is not strictly correct to think of the Fourier transform as being the z-transform evaluated on the unit circle 2021/1/31 Zhongguo Liu_ Biomedical Engineering_shandong Univ11 2021/1/31 Zhongguo Liu_Biomedical Engineering_Shandong Univ. Region of convergence (ROC) ➢The Fourier transforms are not continuous, infinitely differentiable functions, so they cannot result from evaluating a z-transform on the unit circle. it is not strictly correct to think of the Fourier transform as being the z-transform evaluated on the unit circle. cos(w n0 ) ( ) ( ) 0 0 2 2 k      w w k w w k  =−   − + + + +    ( )       = , w w  , w w H e c j w c l p 0 1   sin lp w nc h n n =