高数学课趕媒课件 理工大罗理罗即>> 例1求lm( n-+ +2 n 解 十∴十 下下 n2+n√n2+1 √n+n n 又lm n→0√n2+nn→ 1+ n In =lim n2+1 1,由夹逼定理得 十 m 十 n2+1√n2+2 n+n H tt p: //例1 ). 1 2 1 1 1 lim( 2 2 2 n n n n + n + + + + → + 求  解 , 1 1 1 1 2 2 2 2 +  + + + +  + n n n n n n n n   n n n n n n 1 1 1 lim 2 lim + = → + → 又 = 1, 2 2 1 1 1 lim 1 lim n n n n n + = → + → = 1, 由夹逼定理得 ) 1. 1 2 1 1 1 lim( 2 2 2 = + + + + + n→ n + n n n 