0 22 3 4 11-128.5 an-∑lu k=1 32 2)=(01-3/11-6/1)s 0 )=(00-3/11-2/11) 00113=(001-9) 000a4)=(000-4) =y∑ 解Ly=b,得 )=(1020-17/11-16)( ) 0 u22 u23 u24 = (0 11 - 12 8.5) ( ) T l l 0 1 32 42 ( ) T = 0 1 - 3/11 -6/11 ( ) 0 0 u33 u34 = (0 0 - 3/11 - 2 /11) ( ) T l 0 0 1 43 ( ) T = 0 0 1 -9 ( ) 0 0 0 u44 = (0 0 0 - 4) 解Ly = b,得 ( ) T y y y y 1 2 3 4 ( ) T = 10 20 - 17/11 - 16 å - = = - 1 1 r k rj rj rk kj u a l u rr r k ir ik kr ir u a l u l å - = - = 1 1