矩阵的逆与线性方程组的解 ax1+a12x2+…+arxa=b】 a1+aax+…+ax=b anlx十an2X2+…+AnnXn=bm 一一一一一一一 d11 a12 din a21 a22 d2n .. .: ani an2 ann Xn or,equivalently,letting A =(a),x=(xi),and b =(b:).as Ax =b. If A is nonsingular,it possesses an inverse A,and =AΓb矩阵的逆与线性方程组的解