Z1B=2N6 BRT CCB πW na No CA dnA=-No dt dt dCA二ZAB dC4-乙4e=d2No dt No RT.C.C A+B →P 8RT r=k CA CB k=xdNo πW 计算出的k与实验相差较大 2121 A B CA CB RT Z d N    2 8 0 2 = A + B → P nA = N0 CA A B A A Z dt dC N dt dn − = − 0 = A B A A B C C RT d N N Z dt dC    8 0 2 0 − = = r = k CA CB    RT k d N 8 0 2 = 计算出的 k 与实验相差较大