理想低通抽样的证明 6(t0=) òt-nM)d,(oj22o-@, n=-00 m,))=m06,d)=∑mnT,)6t-nI,) n=-0 .()- Mo)*∑o=n@,) M(o=n,) N=-00 N=-0 7 7 ( ) ( ) T s n t t nT =− = − =− = − n s s T n T ( ) 2 ( ) =− = = − n s T s nTs m (t) m(t) (t) m(nT ) (t ) ( )* ( ) 1 () T s s M T M = 理想低通抽样的证明 = − N=− s s M n T ( )* ( ) 1 = − N=− s s M n T ( ) 1