第12期 李鹏程等：基于离子和分子共存理论的炉渣氧化能力表征 .1571· 表1文献报道的14种含FeO渣系比较 Table 1 Summary of selected 14 FerO-containing slag systems 序号 渣系 炉渣成分（质量分数）/% 实验温实验文献 CaO SiO2 MgO FeO Fe203 MnO Al203 P205 度/K次数 来源 81 CaO-FeO-Fe203 4.32 0 0 53.959.84 0 0 0 1673 19 3 29.03 85.51 17.01 s2 CaO-SiO2- 2.80 16.50 0 22.600.40 0 0 0 1531 65 9 FeO-Fe2Os 35.70 53.00 70.80 3.40 1643 s3 CaO-SiO2-MgO- 28.6029.6005.00 2.00 0 0 12.00 0 1673 48 [10] FeO-Al2Os 46.60 37.4 20.00 10.00 CaO-SiO2-FeO- 2.20 20.90 0 24.300.70 3.90 0 0 1523 75 [1叫 Fe203-MnO 32.20 50.40 64.80 4.60 15.70 1647 s5 Ca0-SiO2-Mg0-28.42 30.79 16.420.65 0.03 0 6.28≈ 0 1823 17 [12] FeO-Fe2O3-Al2O3 40.45 36.53 29.72 4.74 1.13 8.20 s6 SiO2-FeO- 0 4.70 0 3.99≈ 0.471.00 0 1723 30 [4 Fe2O3-MnO 40.40 78.05 10.40 70.75 s7 Cao-SiO2-MgO- 19.67 8.86 2.78 6.44~ 0 0 1.23 1873 108 [13 FeO-P2O5 57.87 30.54 23.90 51.98 8.71 1923 s8 MgO-FeO-205 0 0 1.20 46.511.97 0 14.80~ 1673 35 5 Fe203-P 15.23 76.52 5.98 35.08 s9 Cao-SiO2-FeO 0.95 1.20 0 4.43~ 0 0 0 0 1873 52 [14,42] 46.14 59.90 90.12 s10 CaO-FeO- 0.42~ 0 0 38.491.09 0 0 11.45 1673 54 [5 Fe2O3-P2O5 22.84 80.83 7.61 37.59 s11 SiO2-FeO-Fe203 0 18.20 0 63.800.40 0 0 0 1531 21 9 35.80 78.30 3.80 1643 s12 Cao-SiO2-MgO- 13.80 0.80 0.48 0.93 0.08 0 9.66 1723 76 FetO-Al2O3 53.97 14.79 9.18 57.25 22.04 34.66 s13 Cao-SiO2- 9.70 11.11 0 15.81 6.30 0 0 1.05 1573 29 15) FetO-P205 49.82 49.82 52.42 22.81 4.63 s14* Cao-SiO2-MgO-36.20~ 9.10 6.19~ 5.56 8.810.67 1.70 1.01 1929 27 t FeO-Fe2O3-MnO- 53.02 19.21 9.25 16.47 27.59 1.28 4.34 1.70 1986 Al203-P205 b4=(N +2Ner2+Nels Ne26 3Ne32+4Ne33). b7 (N7 Nc4 7Ne5 Nc6 2Ne7 +6Ncs+ 1 Ne11+Ne13+Ne16+3Nc17+Nc18+Nc19+ ∑m=(专M4+2K82N+KgV4N,+ 2Ne24)∑ni=(N?+KaNN?+7K号N2N9+ K86NAN5+3K2N3Ns+4KNANs) KeNN7+2KNN2+6KeNN9+KeN3N7 ∑n=n唱o, +K3N4N?+K6N6N?+3K,N2W9+ (7) KesN?N2N7+KeNN2N7+2KN3N2NS) b5 (N5 Nc25 Nc26 Nc27 Ne28)>ni ∑n:=nAl203' 0) (Ns KesN1N5 Ke6NaN5 KeN3N5+ bs =(Ns Ne29 Ne30 Ne31 Nxc32 Nc33+ K3sN6Ns)∑n=ne2oa' Ne34 Ne35 Nc36)>ni =(Ns Keg NiNs+ (8) KeoN3Ns+KeNiNs+Ke2NNs+KeaNANs +KeNaNs +kesN3Ns +KeNNs)- bg=(专%+e4+2Nes+V.16+N28+3Ne3a】 ∑n:=n唱20s' ∑m=(6+K:%+2KNG+ (11) Ke6N5N7+KesN6N5 +3KNNs) 平衡条件下CaO-SiO2-Mg0-FeO-Fe2O3-MnO- ∑ni=n唱ino, A12O3-P2O5渣系所有结构单元的摩尔分数之和等 (9) 于1.0.据此，可得到第 12 期 李鹏程等：基于离子和分子共存理论的炉渣氧化能力表征 1571 ·· 表 1 文献报道的 14 种含 FetO 渣系比较 Table 1 Summary of selected 14 FetO-containing slag systems 序号 渣系 炉渣成分 (质量分数)/% 实验温 实验 文献 CaO SiO2 MgO FeO Fe2O3 MnO Al2O3 P2O5 度/ K 次数 来源 s1 CaO-FeO-Fe2O3 4.32∼ 0 0 53.95∼ 9.84∼ 0 0 0 1673 19 [3] 29.03 85.51 17.01 s2 CaO-SiO2- 2.80∼ 16.50∼ 0 22.60∼ 0.40∼ 0 0 0 1531∼ 65 [9] FeO-Fe2O3 35.70 53.00 70.80 3.40 1643 s3 CaO-SiO2-MgO- 28.60∼ 29.60∼0 5.00∼ 2.00∼ 0 0 12.00 0 1673 48 [10] FeO-Al2O3 46.60 37.4 20.00 10.00 s4 CaO-SiO2-FeO- 2.20∼ 20.90∼ 0 24.30∼ 0.70∼ 3.90∼ 0 0 1523∼ 75 [11] Fe2O3-MnO 32.20 50.40 64.80 4.60 15.70 1647 s5 CaO-SiO2-MgO- 28.42∼ 30.79∼ 16.42∼ 0.65∼ 0.03∼ 0 6.28∼ 0 1823 17 [12] FeO-Fe2O3-Al2O3 40.45 36.53 29.72 4.74 1.13 8.20 s6 SiO2-FeO- 0 4.70∼ 0 3.99∼ 0.47∼ 1.00∼ 0 0 1723 30 [4] Fe2O3-MnO 40.40 78.05 10.40 70.75 s7 CaO-SiO2-MgO- 19.67∼ 8.86∼ 2.78∼ 6.44∼ 0 0 0 1.23∼ 1873∼ 108 [13] FeO-P2O5 57.87 30.54 23.90 51.98 8.71 1923 s8 MgO-FeO-2O5 0 0 1.20∼ 46.51∼ 1.97∼ 0 0 14.80∼ 1673 35 [5] Fe2O3-P 15.23 76.52 5.98 35.08 s9 CaO-SiO2-FeO 0.95∼ 1.20∼ 0 4.43∼ 0 0 0 0 1873 52 [14,42] 46.14 59.90 90.12 s10 CaO-FeO- 0.42∼ 0 0 38.49∼ 1.09∼ 0 0 11.45∼ 1673 54 [5] Fe2O3-P2O5 22.84 80.83 7.61 37.59 s11 SiO2-FeO-Fe2O3 0 18.20∼ 0 63.80∼ 0.40∼ 0 0 0 1531∼ 21 [9] 35.80 78.30 3.80 1643 s12 CaO-SiO2-MgO- 13.80∼ 0.80∼ 0.48∼ 0.93∼ 0.08∼ 0 9.66∼ 0 1723 76 [1] FetO-Al2O3 53.97 14.79 9.18 57.25 22.04 34.66 s13 CaO-SiO2- 9.70∼ 11.11∼ 0 15.81∼ 6.30∼ 0 0 1.05∼ 1573 29 [15] FetO-P2O5 49.82 49.82 52.42 22.81 4.63 s14* CaO-SiO2-MgO- 36.20∼ 9.10∼ 6.19∼ 5.56∼ 8.81∼ 0.67∼ 1.70∼ 1.01∼ 1929∼ 27 [7] FeO-Fe2O3-MnO- 53.02 19.21 9.25 16.47 27.59 1.28 4.34 1.70 1986 Al2O3-P2O5 b4 = (1 2 N4 + 2Nc12 + Nc13 + Nc26 + 3Nc32 + 4Nc33)· Pni = (1 2 N4 + 2K ª c12N2N2 4 + K ª c13N4N7+ K ª c26N4N5 + 3K ª c32N3 4 N8 + 4K ª c33N4 4 N8)· Pni = n 0 FeO, (7) b5 = (N5 + Nc25 + Nc26 + Nc27 + Nc28) Pni = (N5 + K ª c25N1N5 + K ª c26N4N5 + K ª c27N3N5+ K ª c28N6N5) Pni = n 0 Fe2O3 , (8) b6 = (1 2 N6 + Nc14 + 2Nc15 + Nc16 + Nc28 + 3Nc34)· Pni = (1 2 N6 + K ª c14N2N6 + 2K ª c15N2N2 6 + K ª c16N5N7 + K ª c28N6N5 + 3K ® c34N3 6 N8)· Pni = n 0 MnO, (9) b7 = (N7 + Nc4 + 7Nc5 + Nc6 + 2Nc7 + 6Nc8+ Nc11 + Nc13 + Nc16 + 3Nc17 + Nc18 + Nc19+ 2Nc24) Pni = (N7 + K ª c4N3 1 N7 + 7K ª c5N12 1 N7 7 + K ª c6N1N7 + 2K ª c7N1N2 7 + 6K ª c8N1N6 7 + K ª c11N3N7 +K ª c13N4N7 + K ª c16N6N7 + 3K ª c17N2 2 N3 7 + K ª c18N2 1 N2N7 + K ª c19N1N2 2 N7 + 2K ª c24N2 3 N2 7 N5 2 )· Pni = n 0 Al2O3 , (10) b8 = (N8 + Nc29 + Nc30 + Nc31 + Nxc32 + Nc33+ Nc34 + Nc35 + Nc36) Pni = (N8 + K ª c29N2 1 N8+ K ª c30N3 1 N8 + K ª c31N4 1 N8 + K ª c32N3 4 N8 + K ª c33N4 4 N8 +K ª c34N3 6 N8 + K ª c35N2 3 N8 + K ª c36N3 3 N8)· Pni = n 0 P2O5 . (11) 平衡条件下 CaO-SiO2-MgO-FeO-Fe2O3-MnO￾Al2O3-P2O5 渣系所有结构单元的摩尔分数之和等 于 1.0. 据此，可得到