二、广义传输线理论 Case 1 TEM情况(E2=0,H2=0) TEM( Transverse Electromagnetic)也即电和磁都只有 横向分量,E,=0,H=0。这时横向方程 oH JOck (11-8) OE E1=e(=) H1=h,(=)二、广义传输线理论 Case 1 TEM 情况(Ez=0,Hz=0) TEM(Transverse Electromagnetic)也即电和磁都只有 横向分量,Ez =0,Hz =0。这时横向方程 z H z j E z E z j H t t t t = = − (11-8) E eV z H h I z t t t t = = ( ) ( ) (11-9)