Only the circumferential displacement takes place只有环向位移 P b Fig.4.2.1 the angle of rotation of pa will be a=(AA"-PP)/ Pa=ue+oue/ardr)-ue/dr= oue/ar the angle of rotation of Pb will be p <pop PPNOP=-Uo/ re=0+β=u0ru/r 徐汉忠第一版20007 弹性力学第四章徐汉忠第一版2000/7 弹性力学第四章 11 Only the circumferential displacement takes place只有环向位移 • the angle of rotation of PA will be =(AA-PP)/ PA =[(u+u /rdr)-u ]/dr= u /r • the angle of rotation of PB will be  =- <pop  =- PP/OP=-u /r • rr =+=u /r-u /r