写出平衡方程求解 ∑Fx=0 Ssin30-Tc sin45cos300-ID sin45cos30=0(1) ∑Fp=0 TAcOS45+ TACOS45°=0 (2 ∑Fz=0 10+Scos30° TsIn45°sin30°+sin45°sin300=0(3) 联立(1)-(3)式得: S=8.660kN TC=TD-3.535 KN 1414 写出平衡方程求解  Fix = 0 S sin30o -TC sin45o cos30o -TD sin45o cos30o = 0 (1)  Fiy = 0 -TC cos45o +TD cos45o = 0 (2)  Fiz = 0 - 10+Scos30o+TC sin45o sin30o+TD sin45o sin30o = 0 (3) 联立(1)---(3)式得： S = 8.660 kN TC = TD = 3.535 kN