Chls10-2 网络拓扑的基本概念 RI 11 20 12 +11 12 +us R2 us +rl+ 10V 2 8 10V u12Q u?R2 8 (b) 分析图(a),(b)中的u1,il,u2,ni2? S 10 R1+R,2+8 l(4)41=l2=l4=10() U110 l4=Ri=2×1=2() l1 =5(4 R,2 U,10 l2=R2i2=8×1=8) 25() R28Ch1s10-2 分析图(a), (b)中的u1, i1, u2, i2? (A) R R u i i S 1 2 8 10 1 2 1 2 = + = + = = u u u (V ) 1 = 2 = s =10 (a) (b) 一. 网络拓扑的基本概念 u Ri 2 1 2(V) 1 = 1 1 =  = u R i 8 1 8(V) 2 = 2 2 =  = (A) R U i 5 2 10 1 1 1 = = = (A) R U i 1.25 8 10 2 2 2 = = =