●KCL、KVL的运算形式 ①KCL∑()=0 ∑4(s)=0 k=1 ②KL∑v()=0 ∑V(s)=0 ●支路关系的运算形式 R R V(S) R (SR /(s) +V(s) ②L V,(s)=LSl, (S)-Li, (0_) 0) i2(0) 1(s)=V(s)+ →(s)L2(0) VI(S)KCL、KVL的运算形式 ①KCL 1 ( ) 0 n k k i t =  = 1 ( ) 0 n k k I s =  = ②KVL 1 ( ) 0 n k k v t =  = 1 ( ) 0 n k k V s =  = 支路关系的运算形式 ①R ( ) ( ) v t R i t = ( ) ( ) V s R I s = ②L ( ) ( ) L L di t v t L dt = ( ) ( ) (0 ) V s LsI s Li L L L = − − 1 (0 ) ( ) ( ) L L L i I s V s Ls s − = + Ls ( ) L I s ( ) + V s L − − + (0 ) LiL − ( ) L I s ( ) V s L + − (0 ) L i s − 1 Ls I s( ) + V s( ) − R