lk 0 设D =|k1 k 11 1 n k D d t (o le D 2 d t (e e k k 1 则 D D D2 上n nn n n nk k k k k k b b b b c c c c a a a a D 1 1 1 1 1 1 1 1 1 1 1 1 0 设 = det( ) , 1 11 1 1 k k k k ij a a a a D a = = det( ) , 1 11 1 2 n nn n ij b b b b D b = = . 则 D = D1D2