Review 时变电磁场的边界条件 n×(E2-E)=0 n:(B2-B)=0 n×(i2-i)=Js +(J2n=Jin)=- ops 8t (D,-D)=Ps 。时变电磁场的能量 (xd-av+1JEav F=:F)-nx(nxF)=En+Fi V×A=F台(V,×An+Vn×A),+(V,×A)n=E+Fn lexu@mail.xidian.edu.cnReview 时变电磁场的边界条件 时变电磁场的能量 lexu@mail.xidian.edu.cn 2 ˆˆˆˆˆ () ( ) ˆ F n n F n n F F n Ft = ⋅ −× × = + n t ( )( ) ∇× = ⇔ ∇ × +∇ × + ∇ × = + AF A A A FF t n n tt t tn t n 2 1 nE E ˆ ×−= ( )0 2 1 ˆ ( ) S nH H J ×−= 2 1 nB B ˆ ⋅−= ( )0 2 1 ˆ ( ) S nD D ⋅−= ρ ( ) 2 1 S tS n n JJJ t ∂ρ ∇ ⋅ + − =− ∂ 1 1 ( ) S V 2 2 V E H dS B H D E dV J EdV t ∂ − × ⋅ = ⋅+ ⋅ + ⋅ ∂ ∫∫ ∫ XIDIAN UNIVERSITY LEXU@MAIL.XIDIAN.EDU.CN