fim()=mla ∫m(2)=0.(=1,2,) 故 0 1 f(i=a +a 0 0 21 22221 21 f(4)f(41)2() fm(2) (m +him+() fm(4) f(4)f()12(4) f(4)f(4) (m+1)! f(2) fm(2) f2)(4) f(4) f() f(4 f() 这就是说,f(J)仍为上三角矩阵,在与主对角线平行的斜线上各元素均相等,而 其第一行元素依次为i m m f ( ) m!a ( )  = ( ) 0,( 1,2,...) ( ) = = + f l i m l  故 0 1 2 2 2 2 2 2 1 0 1 0 1 1 ( ) 0 1 0 1 1 2 1 0 2 1 1 0 2 i i i i i i i i i f J a a a                     = +         + +   ' (2) ( ) ( 1) ( ) ' (2) ' ( 1) ( ) ' (2) ' (2) ' 1 1 1 1 ( ) ( ) ( ) ... ( ) ( ) ... ( ) 2! ! ( 1)! ! 1 ( ) ( ) ( ) 2 ! 1 ( ) ( ) ( ) ( 1)! 1 ( ) ( ) ! 1 ( ) ( ) 2 ! 1 ( ) ( ) ( ) 2 ! ( ) ( ) ( ) m m mi i i i i i i i i i i m i i i m i i i i i i i i i i f f f f f f m m m f f f f f f m f f m f f f f f f f f                       + + + + =       这就是说, ( ) i f J 仍为上三角矩阵, 在与主对角线平行的斜线上各元素均相等, 而 其第一行元素依次为