(6)若何可积,则f几乎处处有限 证明:令E=EDC 则E323且M+=mEn= lim En 1→0 对每个n,有四mE三(到/(x+ 所以lmmE=0 从而mEmn==m(⌒En)=m( lim e)= lim mE=0 1→0O 1→0(6) 若f可积,则f几乎处处有限. 证明: 令E E n f n = [| | ] lim 0 n n mE → 所以 = nm E f x dx f x dx + E E n n 对每个 | ( )| | ( )| n,有 ( ) (lim ) lim 0 1 [ | | ] = = = = → → = =+ n n n n n n 从而mE f m E m E mE [| | ] 1 , lim f n n n n E E E =+ = → 则则EE E E 1 1 2 3 = = E2 E3 且