2015 USA Physics Olympiad Exam Part A 11 which is derivable from the Clausius-Clapeyron relation We are also approximating oP/OT as a constant,given by or ap or,after dropping various notational reminders, 9-(v8)() BvT or 0P.(6×10-4K-1) ∂T≈(5×10-10Pa-1 ≈10Pa/K which implies that any very small change in the temperature of the liquid in a fixed volume will result in a very large change in the pressure. 240 200 B C,W,X,Y 160 120 80 E.......... A 40 … D,Z 0 280 300 320 340 360 380 400 Temperature (K) Copyright C2015 American Association of Physics Teachers2015 USA Physics Olympiad Exam Part A 11 which is derivable from the Clausius-Clapeyron relation We are also approximating ∂P/∂T as a constant, given by  ∂P ∂T  V  ∂V ∂P  T  ∂T ∂V  P = −1 or  ∂P ∂T  V = −  ∂P ∂V  T  ∂V ∂T  P or, after dropping various notational reminders, ∂P ∂T =  −V ∂P ∂V   1 V ∂V ∂T  = βV T βP V or ∂P ∂T ≈ (6 × 10−4 K−1 ) (5 × 10−10 Pa−1) ≈ 106 Pa/K which implies that any very small change in the temperature of the liquid in a fixed volume will result in a very large change in the pressure. 280 300 320 340 360 380 400 0 40 80 120 160 200 240 Temperature (K) Pressure (kPa) A B C, W, X, Y D, Z Copyright c 2015 American Association of Physics Teachers