复变画数 1901 Complex Analysis and Integral Transform 1=cos0+isin o k=0时,=。=cos0+isin0=1 k=时, Z,=cOs-+I Sin 2 k=2时,z,=Cos丌+isnx=-1 3丌 3丌 k=3时,3 coS-+i sin 2 z3+z2+z+1=0根为i,-1,-i 且z3+z2+2+1=(z-i)z+1)(x+i)张 长 华 复变函数与积分变换 Complex Analysis and Integral Transform k = z = + i = −i 2 3 sin 2 3 3 , cos 3   时 1= cos0+isin 0 k = 0时, z0 = cos0+isin 0 =1 k = z = + i = i 2 sin 2 1 , cos 1   时 k = 2时, z2 = cos +isin  = −1 3 2  + + + = − − z z z i i 1 0 , 1, 根为 3 2 且z z z z i z z i + + + = − + + 1 ( )( 1)( )