二、解下列各题(6分×7=42分) 1.求极限1im tan x x-→0 1-cosx lim- tanx In 解:lim ex-01-cosx x-→0 xsec2 x-tanx tan x explim tan x =exp lim x-→0 X→0 x-sinxcosx 1-cos2x exp 2- x→0 cos 0 3x2 =e3二、解下列各题(6分7=42分) 1 1 cos 0 tan 1 lim x x x x − → .求极限 0 1 1 tan 1 cos lim ln 1 cos 0 tan lim x x x x x x x e x → − − → = 解: 2 2 0 0 2 sec tan 1 tan tan exp lim ln exp lim 1 2 x x x x x x x x x x x x → → − = = 3 2 0 sin cos 1 exp lim cos x x x x → x x − = 2 0 1 cos 2 exp lim x 3 x → x − = 2 3 = e